20260627 160152
How can I convert this date code to one wihich is preccable by JMP to do a time axis plot on x axis ?
Carlo
I assume you get this as a string somewhere -> In Format() with format pattern
In Format("20260627 160152", "Format Pattern", "<YYYY><MM><DD> <hh24><mm><ss>")
This should convert it to JMP's datenum which you can then format as needed by using column properties for example. If you have the value in a column, you could try to mess with direct format pattern formatting, but using formula with In Format() is safer option (and easier to use in my opinion).
Using dates, times, datetimes and durations in JMP - JMP User Community