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Average the first 100 rows and the last 100 rows of a JMP column.

I have a noisy curve where I need to take average of the extremes and compare to the minimum value.  Thought this would work but doesn't.

Col Mean( :Column_Name W[Index( 1, 100 )] )&nbsp;+ <SPAN>Col Mean( :Column_Name[N Rows() - 99 :: N Rows()] )</SPAN><CODE class="language-jsl">&nbsp;/ 2

Automation and ScriptingRe: Average the first 100 rows and the last 100 rows of a JMP column.

Here is one way of handling the issue

Names Default To Here( 1 );
dt = 
// Open Data Table: Semiconductor Capability.jmp
// → Data Table( "Semiconductor Capability" )
Open( "$SAMPLE_DATA/Semiconductor Capability.jmp" );
column_name = "NPN1";
Col Mean( If( Row() <= 100, Column( column_name ), . ) ) + Col Mean(
	If( Row() >= N Rows() - 99,
		Column( column_name ),
		.
	)
) / 2;


// I think this is a better formula to calculate the mean of the extremes
Col Mean( If( Row() <= 100 | Row() >= N Rows() - 99, Column( column_name ), . ) );

Re: Average the first 100 rows and the last 100 rows of a JMP column.

Try this

(Mean( :Z[Index( 1, 100 )] ) + Mean( :Z[Index( N Rows() - 99, N Rows() )] )) / 2

Re: Average the first 100 rows and the last 100 rows of a JMP column.

I used "Z" as the column name.