930714_zh-CN

liliconcom

将缺失的数字转换为字符

When converting a missing Numeric value to Char, Char() will return ".". Is there a simple way to return ""?

(I know I can wrap with If( Is Missing( )), but this seems unnecessarily cumbersome.

New Table( "Missing Numeric to Char",
	Add Rows( 1 ),
	New Column( "Numeric", Numeric, "Continuous", Format( "Best", 12 ), Set Values( [.] ) ),
	New Column( "Is Numeric Missing?", Numeric, "Continuous", Format( "Best", 12 ), Formula( Is Missing( :Numeric ) ) ),
	New Column( "Char", Character, "Nominal", Formula( Char( :Numeric ) ) ),
	New Column( "Is Char Missing?", Numeric, "Continuous", Format( "Best", 12 ), Formula( Is Missing( :Char ) ) ),
	New Column( "Really cumbersome method", Character, "Nominal", Formula( If( Is Missing( :Numeric ), "", Char( :Numeric ) ) ) ),
	New Column( "Is Really cumbersome method missing?",
		Numeric,
		"Continuous",
		Format( "Best", 12 ),
		Formula( Is Missing( :Really cumbersome method ) )
	)
);

自动化和脚本编写基础数据分析与建模消费者和市场研究数据融合与清理回复：将缺失的数字转换为字符

我认为最简单的方法是直接使用“If + Is Missing”。像你这样使用“that”更好（更容易理解），但你也可以省略“”。

If(!IsMissing(:numeric), Char(:numeric))

如果不需要公式，只需更改数据类型即可。

回复：将缺失的数字转换为字符

谢谢。虽然不如我预期的那么优雅，但能用。