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JSL coding debug - help needed with "Label"

hasanurkhan

Hello,

In my JSL code, I am using

dtt<<Set Label Columns (:skew);

and I can see in the table that label icon is being added next to skew. Then I am using graph builder and within that routine, I have

Show labels(1),

But when plots are being generated, it is not showing Label. Can you please help on this? Do I need to add anything else?

Thanks much

Accepted answers

All comments

jthi

Usually you enable labels from Label section on the left (this can be different for different plot types)

After you are happy with your graph builder, copy the script

Names Default To Here(1);
dt = Open("$SAMPLE_DATA/Cities.jmp");
dt << Set Label Columns(:City, :State);

gb = dt << Graph Builder(
	Size(528, 454),
	Show Control Panel(0),
	Variables(X(:Longitude), Y(:Latitude)),
	Elements(Points(X, Y, Legend(3), Label("Label by Row")))
);

hogi

you have to activate the labels in the control panel:

dt = Open( "$SAMPLE_DATA/Big Class.jmp" );
:name<< Label( 1 ); // no effect, label is already activated by default for this column
Graph Builder(
	Size( 451, 447 ),
	Graph Spacing( 4 ),
	Variables( X( :height ), Y( :weight ), Overlay( :sex ) ),
	Elements( Points( X, Y, Label( "Label by Row" ) ), Smoother( X, Y ) )
);

hogi

As an alternative, you can tag rows with the "label" flag - and show labels for the tagged rows:

hasanurkhan

Thank you for the tips but unfortunately still Not working. I highlighted in bold the lines in my JSL.

dtt<<Set Label Columns (:skew);

Summarize(dtt, byGroup0 = by (:layout));

Summarize( dtt, byGroup1 = by( :Label ));

Summarize( dtt, byGroup2 = by( :Vt_flavor));

Summarize( dtt, byGroup3 = by( :Z_width));

For (nn =1, nn <= N Items (byGroup0), nn++,

For ( ii = 1, ii <= N Items( byGroup1 ), ii++,

For ( jj = 1, jj <= N Items( byGroup2 ), jj++,

For ( kk = 1, kk <= N Items( byGroup3 ), kk++,

dtt << select where(:Label == byGroup1[ii] & :Vt_flavor == byGroup2[jj] & :Z_width == byGroup3[kk] & :layout ==byGroup0[nn] );

//show(ii,jj,kk,bygroup1[ii],bygroup2[jj],bygroup3[kk]);

sel = dtt << get selected rows;

If( n rows(sel) > 0,

//show("inside",ii,jj,kk);

dt = dtt << subset( selected rows(1), selected columns(0));

gb = dt << Graph Builder(

Size( 266, 228 ),

Show Control Panel( 0 ),

Variables( X( :nmos ), Y( :pmos ), Overlay( :PDK ) ),

Elements( Points( X, Y, legend( 5 ), Label("Label by Row") ) ),

Show labels(1),

SendToReport(

Dispatch(

{},

"nmos",

ScaleBox,

{Label Row(

{Show Major Grid( 1 ), Show Minor Labels( 1 ), Show Minor Grid( 1 )}

)}

hogi

could you please generate a code - as short as possible.
Starting with loading a data table , e.g.

dt = Open( "$SAMPLE_DATA/Big Class.jmp" );

and post it via:

Getting fast helpful answers to your questions
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hasanurkhan

My sincere apology for dumb questions. Not sure what you meant by "Activate the label". I am just running JSL on my database and not clicking on any GUI to activate anything. I thought that setting the column "skew" as label and then what you suggested to add "Label by row" - it should work? Can you please elaborate on the activation part in JSL script (not clicking on any GUI)? Thanks

hogi

please share your code and we can check ...

The smart/lazy way to use JMP:
use the GUI and let JMP generate the code.

hasanurkhan

Also I am generating hundreds of plot, so activating by clicks will not work for my purpose. Thanks

hasanurkhan

Attached are the JSL code and associated data table. Also the graph size is always coming to be Size( 1401, 909 ) even though my code has it as Size (266,228). Appreciate if you can also take a look on that. Thank you so much for your time and help.

output_sorted_test.jsl

output_sorted_test.jmp