迭代创建包含公式的列。我想遍历具有规格限制的列并针对这些列进行分析。
New Column("WM Minus Target", Numeric, "Continuous", Format("Best", 10), Formula(:WN - (:WN << get property("Spec Limits"))["Target"]), Set Selected);此处的脚本接近我想要的。
已解决:当出现规格时,我想写一个失败名称,该如何编写脚本? - JMP 用户社区
只是想知道如何获得更复杂的公式?
谢谢
扳手头
自动化和脚本回复:迭代创建包含公式的列。根据您的分析,您可以为每个测量添加新列,或者先堆叠您的表格并创建单个新列。
为每个参数添加新列
Names Default To Here(1);
dt = Open("$SAMPLE_DATA/Semiconductor Capability.jmp");
cont_cols = dt << Get Column Names("Continuous", "String");
cols_created = {};
For Each({cont_col}, cont_cols,
specs = Column(dt, cont_col) << Get Property("Spec Limits");
If(Is Empty(specs), // skip columns without specs
Continue();
);
cur_target = Try(specs["Target"], .); // If target isn't set -> use 0 (could for example use USL - LSL?)
new_col = Eval(Substitute( // generally I use Eval(EvalExpr()) but in this case this makes expression more clear
Expr(dt << New Column(cont_col || " Minus Target", Numeric, Continuos, Formula(
_curcol_ - _targetval_
))),
Expr(_curcol_), Name Expr(AsColumn(dt, cont_col)),
Expr(_targetval_), cur_target
));
// new_col << Suppress Eval(1);
Insert Into(cols_created, new_col << get name);
);
最后你会得到这样的列(如果你更改列属性,目标将不会更新)

堆叠
Names Default To Here(1);
dt = Open("$SAMPLE_DATA/Semiconductor Capability.jmp");
cont_cols = dt << Get Column Names("Continuous", "String");
ml = dt << Manage Limits(Process Variables(Eval(cont_cols))); // in this case this will open very annoying "help" window due to inconsistencies
dt_limits = ml << Save to Tall Limits Table;
ml << close window;
dt_stack = dt << Stack(
columns(Eval(cont_cols)),
Source Label Column("Measurement"),
Stacked Data Column("Data"),
Output Table("Data Stacked")
);
// If you don't care about LSL/USL they could be dropped from update
dt_stack << Update(
With(dt_limits),
Match Columns(:Measurement = :Variable),
Replace Columns in Main Table(None)
);
dt_stack << New Column("Data Minus Target", Numeric, Continuous, Formula(
:Data - :Target
));
两种数据格式都有其优点和缺点,这取决于您正在做什么。
编辑:
这应该从列属性中获取值,但不会重新评估(如果可以避免,我不会真正使用它)
Names Default To Here(1);
dt = Open("$SAMPLE_DATA/Semiconductor Capability.jmp");
cont_cols = dt << Get Column Names("Continuous", "String");
cols_created = {};
For Each({cont_col}, cont_cols,
specs = Column(dt, cont_col) << Get Property("Spec Limits");
If(Is Empty(specs), // skip columns without specs
Continue();
);
new_col = Eval(Substitute( // generally I use Eval(EvalExpr()) but in this case this makes expression more clear
Expr(dt << New Column(cont_col || " Minus Target", Numeric, Continuos, Formula(
_curcol_ - (_curcol_ << Get Property("Spec Limits"))["Target"]
))),
Expr(_curcol_), Name Expr(AsColumn(dt, cont_col))
));
//new_col << Suppress Eval(1);
Insert Into(cols_created, new_col << get name);
);
回复:迭代创建包含公式的列。Jim 的 Eval() 解决方案应该与如何使公式在我的示例中正确显示类似。
回复:迭代创建包含公式的列。不使用 Eval(Evalexpr()) 不允许在执行之前完全展开公式代码。尝试下面我修改后的代码
Names Default To Here( 1 );
dt =
// Open Data Table: semiconductor capability.jmp
// → Data Table( "semiconductor capability" )
Open( "$SAMPLE_DATA/semiconductor capability.jmp" );
colNames = dt << get column names( continuous, string );
For Each( {xcol}, colNames,
col = xcol;
theTarget = (Column( Eval( col ) ) << get property( "Spec Limits" ))["Target"];
Eval(
Eval Expr(
New Column( col || " Minus Target",
Numeric,
"Continuous",
Format( "Best", 10 ),
Formula( As Column( Eval( col ) ) - Expr( theTarget ) )
)
)
);
);回复:迭代创建包含公式的列。看起来很有趣,但给了我一个错误。名称未解析:theTarget 在访问或评估“theTarget”,theTarget/***###*/
回复:迭代创建包含公式的列。代码有效,但是当我查看结果列中的公式时,它看起来像这样。
As Column( Column( i ) ) - lstTargets[j]
回复:迭代创建包含公式的列。还有另一种方法
Names Default To Here( 1 );
dt =
// Open Data Table: semiconductor capability.jmp
// → Data Table( "semiconductor capability" )
Open( "$SAMPLE_DATA/semiconductor capability.jmp" );
colNames = dt << get column names( continuous, string );
For each( {col}, colNames,
Eval(
Eval Expr(
theTarget = (Column( Eval( col ) ) << get property( "Spec Limits" ))["Target"];
New Column( Expr( col ) || " Minus Target",
Numeric,
"Continuous",
Format( "Best", 10 ),
Formula( As Column( Eval( col ) ) - Expr( theTarget ) )
);
)
);
);回复:迭代创建包含公式的列。这是一种方法。使用关联数组而不是 2 个列表可能更优雅,但使用 2 个列表对我来说更容易理解:
Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Semiconductor Capability.jmp" );
lstCols = {};
lstTargets = {};
//get cols with targets
For Each( {i}, 1 :: N Col( dt ),
t = .;
Try( t = (Column( i ) << Get Property( "Spec Limits" ))["Target"], );
If( !Is Missing( t ),
Insert Into( lstCols, i );
Insert Into( lstTargets, t);
);
);
//make formulas
For Each( {i, j}, lstCols,
//i = 5; j = 1;
dt << New Column( char(Column Name( i )) || " Minus Target",
Numeric,
"Continuous",
Format( "Best", 10 ),
Formula( as column(Column( i )) - lstTargets[j] )
)
);
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