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Why does regex replacement not remove empty lines?

The purpose is to download web content, keep the visible content, and remove lines with only Spaces.
I use the following JSL but can't remove blank lines?

 

Thanks!

u = "https://www.jmp.com/support/help/zh-cn/17.2/jmp/jsl-terminology.shtml";
txt = Load Text File( u );
a = Length( txt );
t1 = Regex( txt, "<(.[^>]{0,})>", "", globalreplace );
t2 = Regex( t1, "  ", "", globalreplace );
t2 = Regex( t2, "^( {0,})\!n", "", globalreplace );
t2 = Regex( t2, "\!n\!n", "", globalreplace );

Basic Data Analysis and ModelingWindows回复： Why does regex replacement not remove empty lines?

The same JSL can replace such empty lines, I do not know what went wrong?

Thanks!

txt =
"-->\!n\!n\!n\!nJSL Terminology\!n\!n\!n\!n\!n\!n\!nScripting Guide > Introduction to Writing JSL Scripts > JSL Terminology";
t1 = Regex( txt, "\!n\!n+", "", globalreplace );

回复： Why does regex replacement not remove empty lines?

I used hex(t2) to see what was left in the string:

...0A0D0A0D0AE69CACE7BD91E7AB99E59CA8E590AFE794A8204A
61766153637269707420E79A84E68385E586B5E4B88BE69588E69E
9CE69C80E4BDB3E380820D0A0D0A0D0A0D0A0D0A0D0A0D0A0D0A"

The 0D0A pairs are CR LF pairs. \!n is JMP's escape for LF. I'd use this regex to match a run of any mix-and-match of CR and LF:

t2 = Regex( t2, "[\n\r]+", "", globalreplace );

Regex does not use the ! in the escape.

回复： Why does regex replacement not remove empty lines?

...and typically, I'd replace runs of white space with

t2 = Regex( t1, "[ \n\r]+", " ", globalreplace );

(a space is also in the character set, and the replacement is a space) to keep the output a little more like the input, with the runs of white space compressed to a single space. (I removed the other t2= statements as well.)

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pt editor. Note: The only white space exception is two-character operators (suc
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息？有问题？从 JMP 用户社区得到解答 (community.jmp.com). 本网站在
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