remove string that contains number from text

Question

Hi,
 is that a way to remove any string that contain numbers using JSL?

Example:
I ate 4 apples and 2 bananas
the model number is 0998GBELS

03/45 is the ratio to check

Targeted Output:

I ate apples and bananas
the model number is

is the ratio to check

jthi · Answer

Not sure i this would work in all situations but it does for these examples

Names Default To Here(1);

strs = {
"I ate 4 apples and 2 bananas",
"the model number is 0998GBELS",
"03/45 is the ratio to check"
};

result2 = Transform Each({str}, strs,
	Regex(str, "\w*\S*\d+\w*\S*", "", GLOBALREPLACE)
);

show(result2); // result2 = {"I ate apples and bananas", "the model number is ", " is the ratio to check"};

Edit:

I think that regex can be simplified a bit to

Regex(str, "\S*\d+\S*", "", GLOBALREPLACE)

https://regex101.com/r/PM4UQn/1

dadawasozo · Answer

I have many lines to process (in hundred millions), doing so will cause higher latency. I wonder if there is a better way to remove those strings that contain number with lower latency ?

txnelson · Answer

This works, but someone familiar with Regular Expressions would be able to simplify the script

Names Default To Here( 1 );
theString = "I ate 4 apples and 2 bananas
the model number is 0998GBELS

03/45 is the ratio to check";

theList = Words( theString, " \!n\!r\!t" );
adjustedString = "";
For Each( {member}, theList,
	Show( member );
//member=thelist[1]
	found = "No";
	If( !Contains( member, "0" ),
		If( !Contains( member, "1" ),
			If( !Contains( member, "2" ),
				If( !Contains( member, "3" ),
					If( !Contains( member, "4" ),
						If( !Contains( member, "5" ),
							If( !Contains( member, "6" ),
								If( !Contains( member, "7" ),
									If( !Contains( member, "8" ),
										If( !Contains( member, "9" ),
											adjustedString = Trim( adjustedString || " " || member )
										)
									)
								)
							)
						)
					)
				)
			)
		)
	);
);

Show( adjusted String );