nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

I can't even do this simple replace!

lwx228

Not found in the script index, please finish with JSL.Thank you very much!

Accepted answers

ian_jmp

You could use data table subscripting:

NamesDefaultToHere(1);
dt = Open("$SAMPLE_DATA/Big Class.jmp");
Wait(3);
maleRows = Loc(dt[0, "sex"], "M");
dt[maleRows, "sex"] = "boy";

lwx228

I've tried to write JSL in a way that only works with perfectly matched substitutions, but if you don't want to replace only a few characters, how do you write JSL?Thank you!

txnelson

This is one way to do it

dt = Current Data Table();
dt:class[dt << get rows where( dt:class == "A1" )] = "A9";

ian_jmp

OK. So maybe take a look at regular expressions.

txnelson

That is not all the ways it can be coded in JSL to accomplish what you want, but Ian's suggestion is what I would have also suggested as the solution.

All comments

ian_jmp

You could use data table subscripting:

NamesDefaultToHere(1);
dt = Open("$SAMPLE_DATA/Big Class.jmp");
Wait(3);
maleRows = Loc(dt[0, "sex"], "M");
dt[maleRows, "sex"] = "boy";

lwx228

It seems to be quite different from the VBA approach.thank you!

lwx228

I've tried to write JSL in a way that only works with perfectly matched substitutions, but if you don't want to replace only a few characters, how do you write JSL?Thank you!

txnelson

This is one way to do it

dt = Current Data Table();
dt:class[dt << get rows where( dt:class == "A1" )] = "A9";

lwx228

If this is the new case, this JSL is not very efficient.Can the code be improved for the new instance?Thank you!