Plotting gradient colors in JSL, how to use variables to represent specific parameters?

Question

For example, the maximum and minimum values of this: {gradient({Scale Values([200000 0 -200000])})} mx=200000 mn=-200000 {gradient({Scale Values([ma 0 -ma])})}

hogi · Answer

As an alternative you could create the matrix outside of the command and use it via Name Expr(range)

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Cities.jmp" );
obj = dt << Treemap( Categories( :city ), Sizes( :POP ), Coloring( :CO ) );

range = [1 20];
(obj << Get Legend Server()) << Legend Model(
	1,
	Properties(
		0,
		{gradient( Scale Values( Name Expr( range ) ) )}
	)
);

lala · Answer

Thank Jim!

{gradient( {Scale Values( ["
		 || Char( mn ) || " " || Char( mx ) || "] )} )}

txnelson · Answer

This is my old school way of handling this:

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Cities.jmp" );
obj = dt << Treemap( Categories( :city ), Sizes( :POP ), Coloring( :CO ) );
treemapGBPref = Get Platform Preference( treemap( "Use Graph Builder" ) );
prefVal = Arg( Arg( Arg( treemapGBPref, 1 ) ) );

mx = 20;
mn = 1;
report = obj << report;
Eval(
	Parse(
		"report << Dispatch(
		{},
		\!"400\!",
		ScaleBox,
		{Legend Model(
			1,
			Properties(
				0,
				{gradient( {Scale Values( ["
		 || Char( mn ) || " " || Char( mx ) || "] )} )},
				Item ID( \!"CO\!", 1 )
			)
		)}
	);"
	)
);

When all else fails, this method always works.  You need to learn it and put it into your tool box.