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如何更新函數中的新表變數值

在函數內更新新表變數值的最佳方法是什麼？此時此刻，我正在這樣做。但是，我發現此 Days 變數不會更新且它將建立一個名為 Days 2 的新變數。

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Big Class.jmp" );
dt << New Table Variable( "Days", 42 );   // In original data table, Days set to default which is 42


// assume below is a new function, and I'm passing dt as input and I want to update the Days variable
myFunction = Function ({dt},
 
 // I want this Days variable get updated with new value below, 100
 dt << New Table Variable ( "Days", 100);
 
 dt << Select Where( :Name( "sex" ) == "F" );
 dt << Subset( Copy formula( 1 ), Suppress formula evaluation( 0 ), Selected Rows( 1 ), Selected columns only( 0 ) );
 dt = Data Table (Current Data Table() << Get Name());
);


myFunction(dt)

</CODE></PRE><P>&nbsp;</P></LINGO-BODY><LINGO-LABS id="lingo-labs-682883" slang="en-US" mode="NONE"><LINGO-LABEL>自動化和腳本編寫</LINGO-LABEL></LINGO-LABS><LINGO-SUB id="lingo-sub-682897" slang="en-US" mode="NONE">回覆：如何更新函數中的新表變數值</LINGO-SUB><LINGO-BODY id="lingo-body-682897" slang="en-US" mode="NONE"><P>腳本索引</P>
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<P>所以使用 << Set Table Variable 而不是建立一個新變數</P></LINGO-BODY><LINGO-SUB id="lingo-sub-683259" slang="en-US" mode="NONE">回覆：如何更新函數中的新表變數值</LINGO-SUB><LINGO-BODY id="lingo-body-683259" slang="en-US" mode="NONE"><P>你好，</P><P>&nbsp;</P><P>感謝您的建議，我認為它有效。除此之外，我對這個變數更新還有一些額外的問題。 你知道JSL如何根據我們在函數外部宣告的新變數來更新資料表變數嗎？ 我修改了程式碼如下，我認為它不起作用。 我希望設定表變數能夠從 a 和 b 變數載入值。</P><P>&nbsp;</P><PRE><CODE class=" language-jsl">Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Big Class.jmp" );
dt << New Table Variable( "Days", 42 );   // In original data table, Days set to default which is 42

// declare new variable, this will be input from user
a = 100;
b = 200;

// assume below is a new function, and I'm passing dt and a as input
myFunction1 = Function ({dt, a},
 
 // I want this Days variable get updated with new value based on a
 dt << Set Table Variable ( "Days", :a);
 
 dt << Select Where( :Name( "sex" ) == "F" );
 dt << Subset( Copy formula( 1 ), Suppress formula evaluation( 0 ), Selected Rows( 1 ), Selected columns only( 0 ) );
 dt = Data Table (Current Data Table() << Get Name());
);

// assume below is a new function, and I'm passing dt and b as input
myFunction2 = Function ({dt, b},
 
 // I want this Days variable get updated with new value based on b
 dt << Set Table Variable ( "Days", :b);
 
 dt << Select Where( :Name( "sex" ) == "M" );
 dt << Subset( Copy formula( 1 ), Suppress formula evaluation( 0 ), Selected Rows( 1 ), Selected columns only( 0 ) );
 dt = Data Table (Current Data Table() << Get Name());
);

myFunction1(dt);
myFunction2(dt);

回覆：如何更新函數中的新表變數值

您的函數指定了 2 個輸入變量，而您在呼叫函數時僅指定一個。
您錯誤地確定了變數的範圍。在腳本中使用 :a 指示 JMP 尋找名為「a」的欄位。變數前面指定的冒號「:」告訴 JMP 該引用指向資料表列。八、從變數引用中刪除冒號或指定 Here:a，當您指定時，這是變數的正式名稱
```
Names Default to Here( 1 );
```

回覆：如何更新函數中的新表變數值

帶錶變量，如果不使用

dt << Set Table Variable

您需要先刪除該變量，然後再次建立它。

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Big Class.jmp" );
dt << New Table Variable( "Days", 42 );   // In original data table, Days set to default which is 42


// assume below is a new function, and I'm passing dt as input and I want to update the Days variable
myFunction = Function ({dt},
 
 // I want this Days variable get updated with new value below, 100
 dt << Delete Table Variable ( "Days");
 dt << New Table Variable ( "Days", 100);
 
 dt << Select Where( :Name( "sex" ) == "F" );
 dt << Subset( Copy formula( 1 ), Suppress formula evaluation( 0 ), Selected Rows( 1 ), Selected columns only( 0 ) );
 dt = Data Table (Current Data Table() << Get Name());
);

回覆：如何更新函數中的新表變數值

哦，我錯過了那部分。知道了。

現在它正在按預期工作。謝謝吉姆。

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