我有一个包含几千列的数据表。 我希望通过另一个变量找到这些列中前“X”个值。 例如，当另一列的值为“大盘股”时，我想知道具有 10 个最高值的列。
在对数据没有任何了解的情况下，最简单的方法可能是首先堆叠数据，然后选择前 10 个值。
这是一种仅用一列即可完成此操作的方法。 您可以将其放入每个列的循环中。 这个帖子有更多的背景。
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//init
n = N Rows();
lstCategories = Associative Array( :Stock Type << Get Values ) << Get Keys;
lstRows = {};
dt = Current Data Table();
dt << Clear Column Selection;
dt << Clear Select;
//loop through each category for first column; save top 10 for each category into lstRows
For Each( {i}, lstCategories,
dt << Select Where( :Stock Type != i );
dt << Hide and Exclude;
dt << Clear Select;
dt << select rows( Loc( Ranking( :"Value 1"n[1 :: n] ) >= n - 10 ) );
t = As List( dt << Get Selected Rows );
Show( i );
Show( t );
dt << Clear Row States;
Insert Into( lstRows, t );
);
//do something with the rows
dt << Select Rows( lstRows );
哇， Loc(Ranking...)太棒了！非常有用！
我刚刚读了这个问题，想知道
@dkraeuter_sunne写道：
具有 10 个最高值的列
- 每一行？
那么可能是
dt = Current Data Table();
nc = N Cols();
Row() = 4;
For Each Row(
If( :Stock Type == "Large Cap Stock",
mx = Max( dt[Row(), 2 :: nc] );
colnumbers = Loc( Ranking( mx - dt[Row(), 2 :: nc] ) <= 10 );
colnames = Transform Each( {col}, As List( colnumbers ), Column( col + 1 ) << get name );
Print( Row(), colnames );
)
);
“第 27 列”及其后列有许多缺失值。这些列是否必须包含在分析中？
