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Re: Durée

Maybe something like this:

For(k=1, k<=6, k++,
 StartValue = Column(k+2)[1];
 For(i=1, i<=6, i++,
  If(num(Column(i+8)[1])>StartValue,break())
 );
 If(i<7, Write(Column("Date début "||(Column(i+8)<<GET name=""></GET>

Re: Duration

thank you for your reply @pauldeen but this is a test database, this script should work for more than 700 columns.

Re: Durée

A bit lazy solution, but it might work

Names Default To Here(1);

dt = Open("$DOWNLOADS/AAAA.jmp");

// would get only numeric columns, but the provided example table is broken...
all_cols = dt << Get Column Names(/*Numeric, */"String"); 
// so first we have to fix the datatable
Remove From(all_cols, 1, 2);
For Each({col_name}, all_cols,
 Column(dt, col_name) << Set Data Type("Numeric");
 Column(dt, col_name) << Set Modeling Type("Continuous");
);

// create list of duration columns
// same amount of columns AND in same order for "number" and duration
date_cols = {};
some_cols = {};

For Each({col_name}, all_cols,
 If(Starts With(lowercase(col_name), "date d"),
  Insert Into(date_cols, col_name);
 , !IsMissing(Regex(col_name, "^\d+$")),
  Insert Into(some_cols, col_name);
 ,
  show(col_name);
 );
);

If(N Items(date_cols) != N Items(some_cols),
 Throw("Column mismatch");
);

// create new columns
dur_cols = {};
For Each({some_col}, some_cols,
 new_col = dt << New Column("duration " || some_col, Numeric, Continuous);
 Insert Into(dur_cols, new_col << get name);
);

// calculation
For Each Row(
 For Each({date_col, idx}, date_cols,
  datesomething = dt[Row(), some_cols[idx]];
  datesomethingvals = dt[Row(), some_cols];
  // to make comparison easier
  datesomethingvals[idx] = .; 
  datesomethingvals[Loc(datesomethingvals < datesomething)] = .; // lazy handling
    
  idx_of_interest = Loc Min(Abs(datesomethingvals - datesomething));
  If(idx_of_interest == 0,
   continue();
  );
  val_of_interest = dt[Row(), date_cols[idx_of_interest]];

  dt[Row(), dur_cols[idx]] = Abs(val_of_interest - dt[Row(), date_col]); // not sure if Abs is correct here
 );
);

// durations for 900 and 4500 for some reason missing from demo data

Re: Duration

thank you for your reply @jthi !

Duration

 

Hello everyone,

 

I have database like below,

 

 

In the comic, the green cells are the results that we would like to obtain.

 

I would like to create a script to calculate durations.

I have "start date" columns and then I have a "number" column which indicates the order of execution.

The goal would be to calculate "start date y - start date x" based on the numbers.

 

I explain myself on an example with the comic strip:

 

1st line : We notice that the column "720" has the number 12 in the cell, so we are looking among all the "number" columns for the first one greater than 12 (here column "740" with the value 21)

So duration 720 would be duration 720 = start date 740 - start date 720.

 

Then for duration 740 it would be duration 740 = start date 9801 - start date 740 with the same principle

 

Here is the script I started writing:

 

dt = Current Data Table();

dur_cols = Filter Each( {col_name}, dt << Get Column Names( "String", Continuous ),
 Starts With( col_name, "Date début" )  
);


num_colnr = Transform Each( {col_name}, dur_cols, Word( -1, col_name ) );

char_cols = dt << Get Column Names ("string", Character); 



wait(1);
N_taches = N Items(dur_cols);
for (i = 1, i <= N_taches, i++, 
 Eval(
  Eval Expr(
   col = dt << New Column ( "durée" || num_colnr[i], Numeric, "Continuous", Format(":jou:hh:m",8));
   col << Formula(
    colidx = Loc(dt[row(), char_cols] > Eval(num_colnr[i]))[1];
    If ( N Items(colidx) > 0,
     val = dur_cols[colidx] - Eval(dur_cols[i]);
     If(IsMissing(val),
      0
     ,
      val
   );
  ,
   0
  );
 );
)));

Thanks for your help !

 

 

Consumer and Market ResearchQuality and Process EngineeringRe: Durée

So? Just up the For loop count number. Or make it dynamic by including N cols() as the upper bound.

If you have allready solved this would you please mark this topic as solved?