我可能會把它寫成 SQL 查詢,但它也可以在 JSL 中完成。 以下是一種可能的選擇(有許多更簡單和更複雜的選擇)
Names Default To Here(1);
dt = New Table("Project Status",
Add Rows(5),
New Column("Project", Character, "Nominal", Formula("Project " || Char(Row()))),
New Column("Start Date", Numeric, "Ordinal", Format("m/d/y", 12), Formula(Date Increment(Today() - In Days(Row() * 10), "Day"))),
New Column("End Date", Numeric, "Ordinal", Format("m/d/y", 12), Formula(Date Increment(Today() + In Days(Row() * 10), "Day")))
);
dt << Run Formulas;
:Start Date << Delete Formula;
:End Date << Delete Formula;
// Add monthyear column based on Start Date
new_col1 = dt << New Column("MonthYear1",
Numeric,
"Ordinal",
Format("m/y", 12),
Formula(Date DMY(1, Month(:Start Date), Year(:Start Date)))
);
new_col2 = dt << New Column("MonthYear2",
Numeric,
"Ordinal",
Format("m/y", 12),
Formula(Date DMY(1, Month(:End Date), Year(:Start Date)))
);
// calculation should be based on min date and max date found from dataset in my opinion
// not based on the found values, but this is easier so I'll use this
date_months = Associative Array(new_col1);
date_months << Insert(Associative Array(new_col2));
dt << Delete Columns({"MonthYear1", "MonthYear2"});
aa_results = Associative Array();
For Each({month_start}, date_months << get keys,
// last day of month
max_day = In Days(Days In Month(Year(month_start), Month(month_start))) + month_start - Time Of Day(month_start);
// some logic to get projects
r = dt << Get Rows Where((:Start Date <= month_start & :End Date >= month_start) | (month_start <= :Start Date < max_day));
aa_results[month_start] = N Items(r);
);
dt_results = New Table("Results",
New Column("MY", Numeric, Continuous, Values(aa_results << get keys)),
New Column("ProjInProg", Numeric, Continuous, Values(aa_results << get values)),
);

你好,我製作了這個示例數據集來展示我正在解決的問題:
New Table("Project Status",
Add Rows(5),
New Column("Project", Character, "Nominal", Formula("Project " || Char(Row()))),
New Column("Start Date", Numeric, "Ordinal", Format("m/d/y", 12), Formula(Date Increment( Today() - In Days( Row() * 10 ), "Day" ))),
New Column("End Date", Numeric, "Ordinal", Format("m/d/y", 12), Formula(Date Increment( Today() + In Days( Row() * 10 ), "Day" )))
);以下代碼將創建一個 5x3 數據表,其中包含 5 個不同項目的開始日期和結束日期。 我想做的是計算數據集中所有月/年組合的“正在進行的項目”。 我的意思是,任何開始日期的項目都應計入該月,直到結束日期已過。 這是我希望製作的圖像示例:

有沒有辦法使用 JSL 將這些計數放入自己的數據表中?
請讓我知道是否可以提供有關我要完成的工作的更多信息。
謝謝