回复：通過軸標籤選擇數據點？可以添加熱圖子圖以允許選擇。
但是有沒有直接的方法，只使用軸標籤？
Names Default to Here(1);
dt = Open( "$SAMPLE_DATA/Big Class.jmp" );
dt << new column("X",Nominal, set each value(1));
Graph Builder(
Variables( X( :age ), Y( :weight ), Y( :height ), Y( :X ) ),
Relative Sizes( "Y", [100 100 15] ),
Elements( Position( 1, 1 ), Points( X, Y, Legend( 12 ) ) ),
Elements( Position( 1, 2 ), Points( X, Y, Legend( 13 ) ) ),
Elements( Position( 1, 3 ), Heatmap( X, Y, Legend( 19 ) ) )
)
回复：通過軸標籤選擇數據點？我更喜歡你的熱圖想法，但這裡有一些幾乎可行的東西，可能有助於推動討論向前發展。 我在想一個數據過濾器而不是軸會起作用，但我找不到擺脫所有控件的方法。
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dt = open ("$SAMPLE_DATA/Big Class.jmp");
nw = New Window( "Graph",
V List Box(
g = Graph Builder(
Size( 754, 634 ),
Show Control Panel( 0 ),
Show Legend( 0 ),
Show X Axis( 0 ),
Show X Axis Title( 0 ),
Variables( X( :age ), Y( :height ), Y( :weight ) ),
Relative Sizes( "Y", [127 128] ),
Elements( Position( 1, 1 ), Points( X, Y, Legend( 18 ) ) ),
Elements( Position( 1, 2 ), Points( X, Y, Legend( 19 ) ) )
),
df = dt <<
Data Filter(
Location( {2831, 76} ),
Width( 741 ),
Add Filter(
columns( :age ),
Where( :age == 17 ),
Display( :age, "Blocks Display" )
)
)
)
);
df << show controls (0);回复：通過軸標籤選擇數據點？我經常在圖中的變量上打開一個 Distribution 平台。 我使用動態鏈接來選擇值並定義選擇子集。 現在我可以使用列名和數據值之間的直方圖來達到同樣的目的。
通過軸標籤選擇數據點？在圖形生成器中，是否可以通過（Shift、Alt、Ctrl）單擊分類/序數軸的標籤來選擇數據點？
即通過單擊“14”，與年齡 = 14 對應的所有數據點都會突出顯示：
大規模定制回复：通過軸標籤選擇數據點？附加主題：
如果將多個列用作分層 X 標籤，則每個子圖和繪圖樣式都可以選擇使用或不使用相應的列作為層次結構的一部分。
這非常有用：
通過取消選擇用作 X 軸上第二級的列，熱圖將僅由第一級分隔，如下所示：
不幸的是，取消選擇列沒有任何效果 - 圖表看起來與選擇和取消選擇“X - 名稱”完全相同:(
Graph Builder(
Variables(
X( :age ),
X( :name, Position( 1 ) ),
Y( :weight ),
Y( :X ),
Color( :age ),
Frequency( :one )
),
Relative Sizes( "Y", [100 15] ),
Elements( Position( 1, 1 ), Points( X( 1 ), X( 2 ), Y ) ),
Elements( Position( 1, 2 ), Heatmap( X( 1 ), Y ) )
)
回复：通過軸標籤選擇數據點？我知道的老話題，但我回應@馬克貝利關於直方圖的評論，這裡是一個例子：
JSL 重新創建此圖：
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