shapeseg() color by average value

Question

I'm trying to color a shapeseg by the average of the contents of its row states (think graph builder).  If there are two contrasting values in the row states, it just doesn't color it however.

Has anyone every had any luck doing this?

Names default to here(1);

dt = open("$SAMPLE_DATA\Big Class.jmp");
ss = Shape Seg(
	{Path( [10 10 1, 10 70 0, 70 70 0, 70 10 -3] ),
		Path( "M20,20 C20,60 60,60 60,20 Z" ), 
		Path( [10 60 1, 10 90 0, 70 90 0, 70 60 -3] )
	},

RowStates(dt, 
		{
			{1, 2}, // two different ones so it's not colored
			{3}, // only one color so it colors 
			{7,10, 16} //three of the same color so it colors
		}
	)
);
New Window( "Shape Seg Example",
	gb = Graph Box()
);
gb << append Seg(ss);

mikedriscoll · Answer

Ok. After I re-read your reply I realized the binning column itself won't help but yeah some sort of separate summary column or table associated with those rows would likely work.

vince_faller · Answer

Yeah it's important to still have that interactivity.  I tried just doing a colmean and coloring by that but I didn't like the way it behaved.  Right now I'm trying to just make a custom private summary table (because it's not exactly a summary) and add a row state handler so that the selection is still there in the main Table.

mikedriscoll · Answer

Same version, 13.2.1 64 bit (standard). Mine plots all 3 paths, and with your updated script it is only coloring the 2 like you mentioned. The third i can color manually (right click, color) but I see it isn't what you want.

I think you are either going to need to create a new height binning column, say 50-54, 55-59, 60-65, etc, and color by that column, and set your row state groups to correspond that column as well, OR color spectrally, and set your row state row lists in the shape seg by those pre-set colors. (not sure what happens if a user changes row colors).