How to delete text before a number

Question

Hello, I've attached my .jmp file that I'm working with it.

I have a column with a variety of descriptions. In it, you will notice that most of them have "Qty #" in which the # could be any value. What I'm trying to do is either delete "Qty #" and everything before that for all of the rows, or just simply split off all of the characters after "Qty #" into its own column. I've been trying to figure this out for an hour and have not been successful. Here's some examples on what I'm trying to do:

Old Column

ELECTRICAL-EA Qty 1 KIT,VARIOUS,,STATOR WINDING REPAIR

New Column (trying to achieve this)

KIT,VARIOUS,,STATOR WINDING REPAIR

Old Column

FITTINGS-EA Qty 1 EDUCTOR,BRZ,4.000 X 4.000 X 2.500,STATIO

New Column (trying to achieve this)

EDUCTOR,BRZ,4.000 X 4.000 X 2.500,STATIO

Any help is much appreciated!

Truncating Characters.jmp

gzmorgan0 · Answer

Oops misread your request:

t0 = Contains( :Column 1, "Qty" );
t1 = Contains( Substr( :Column 1, t0 + 4 ), " " );
If( t0 > 0,
 Substr( :Column 1, t0 + t1 + 4 ),
 :Column 1
);

gzmorgan0 · Answer

There are multiple formulas to do this this is. Try this column formula:

Num( Regex( :Column 1, "Qty\s*(\d*)", "\1" ) )

Regular expressions cane be confusing, so here is an alternative column function. Words(str) breaks up strings; since no delimiter is specified, it breaks them up by spaces (white space).  If qty is found the next word should be the value.

t0 = Contains( Words( Lowercase( :Column 1 ) ), "qty" );
If( t0 > 0,
	Num( Words( :Column 1 )[t0 + 1] )
);