Simplify JSL in transpose column #Hi I am trying to reduce the transpose JSL columns.
Currently, when transpose col from col (3) to col (8), each col needs to be listed specifically.
Can I convert it to transpose between col (3) and col (8)? without list each column name.
Thanks
dt = Current Data Table();
dt << Transpose(
columns(
Column( 3 ),
Column( 4 ),
Column( 5 ),
Column( 6 ),
Column( 7 ),
Column( 8 )
);
ScriptingRe: Simplify JSL in transpose column #Here is one way to do what you want
dt = Current Data Table();
colNames = (dt << get column names(string))[3::8];
dt << Transpose(
columns(
colNames
)
);
Re: Simplify JSL in transpose column #You can index the columns by number:
Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Blood Pressure.jmp" );
dt << Transpose( Columns( 2::6 ), By( :Dose ), Label( :Subject ) );
Re: Simplify JSL in transpose column #Hi, Both solution works great