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Calculating duration between two dates from different years

I am using JSL scripting to run one of my reports that can calucate the duration between two dates. My report has a Start Date in column 'A' and End Date in column 'E' , I want to calcuate the following:

1. Duration between those two days excluding weekends

2, Duration between those two days , start date is 10/31/2012 and end date is 02/20/2013, and when I used the forumla "Formula(Day(:E - :A) )" , Iam getting a value of 10, instead of something bigger. Start Date is in 2012 and end date is in 2013, so do I need to make any change to my script ? The other durations that fall in the same year are calculated properly using the same formula..but the dates that fall in different years are not calculated accurately..

can some one help with the two questions?

thanks,

Re: Calculating duration between two dates from different years

Yes it worked..thankyou so much!!

Re: Calculating duration between two dates from different years

Ok I think I understand the problem. JMP apparently does not follow the ISO 8601 standard (i.e first day of week is monday) but the US tradition of celebrating sunday as the first day of the week. This perfectly explains your results above as my formula assumes the former. However, it's trivial to adapt the formula to take that into account (or any other local definition of day of week or what days that are considered belonging to the weekend).

Try e.g. this:

Try( Sum( 1 < Day Of Week( Index( :A, :E, 86400 ) ) <= 6 ) - 1 )

Below is my test output and it appears to work. The "counter" halts over weekends (sat-sun where I live). Remove the -1 if you by "duration between two dates" mean to include the full duration of both start and end dates. (Here A = today, E = future days)

A	E	Weekday	Working days
2013-04-05	2013-04-05	Friday	0
2013-04-05	2013-04-06	Saturday	0
2013-04-05	2013-04-07	Sunday	0
2013-04-05	2013-04-08	Monday	1
2013-04-05	2013-04-09	Tuesday	2
2013-04-05	2013-04-10	Wednesday	3
2013-04-05	2013-04-11	Thursday	4
2013-04-05	2013-04-12	Friday	5
2013-04-05	2013-04-13	Saturday	5
2013-04-05	2013-04-14	Sunday	5
2013-04-05	2013-04-15	Monday	6
2013-04-05	2013-04-16	Tuesday	7
2013-04-05	2013-04-17	Wednesday	8
2013-04-05	2013-04-18	Thursday	9
2013-04-05	2013-04-19	Friday	10
2013-04-05	2013-04-20	Saturday	10
2013-04-05	2014-04-21	Monday	271
2013-04-05	2015-04-22	Wednesday	533

Re: Calculating duration between two dates from different years

The data is Numeric COntinuous, Date format..and I want to calculate the number of weekdays excluding the weekends.. sample data:-

Planned start date	New Task Completion Date
1/3/2013	1/3/2013
1/3/2013	1/4/2013
1/8/2013	1/8/2013
1/8/2013	1/8/2013
1/9/2013	1/9/2013
1/9/2013	1/9/2013
1/9/2013	1/11/2013
1/9/2013	1/9/2013
1/9/2013	1/10/2013
1/9/2013	1/9/2013
1/10/2013	1/11/2013
1/10/2013	1/11/2013

Re: Calculating duration between two dates from different years

I tried your formula..it is working for few cells..see my data below..using your formula..the rows 1 and 2 contradict..

Planned start date	New Task Completion Date	MS
1/3/2013	1/3/2013	0
1/3/2013	1/4/2013	0
1/8/2013	1/8/2013	0
1/8/2013	1/8/2013	0
1/9/2013	1/9/2013	0
1/9/2013	1/9/2013	0
1/9/2013	1/11/2013	1
1/9/2013	1/9/2013	0
1/9/2013	1/10/2013	1
1/9/2013	1/9/2013	0
1/10/2013	1/11/2013	0
1/10/2013	1/11/2013	0
1/2/2013	1/2/2013	0
1/2/2013	1/8/2013	4
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/7/2013	1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/8/2013	2
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/7/2013	1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/4/2013	1/8/2013	2
1/4/2013	1/4/2013	-1
1/4/2013	1/7/2013	1
1/7/2013	1/8/2013	1
1/4/2013	1/4/2013	-1
1/4/2013	1/4/2013	-1
1/7/2013	1/7/2013	0
1/7/2013	1/9/2013	2
1/10/2013	1/10/2013	0
1/7/2013	1/7/2013	0
1/7/2013	1/7/2013	0
1/7/2013	1/7/2013	0
1/7/2013	1/8/2013	1
1/8/2013	1/9/2013	1
1/7/2013	1/7/2013	0
1/7/2013	1/7/2013	0
1/7/2013	1/8/2013	1
1/7/2013	1/7/2013	0
1/7/2013	1/7/2013	0
1/7/2013	1/8/2013	1
1/8/2013	1/8/2013	0
1/8/2013	1/8/2013	0
1/8/2013	1/9/2013	1
1/9/2013	1/16/2013	5
1/16/2013	1/22/2013	4
1/8/2013	1/8/2013	0
1/8/2013	1/8/2013	0
1/9/2013	1/9/2013	0
1/9/2013	1/10/2013	1
1/10/2013	1/10/2013	0
1/15/2013	1/15/2013	0
1/15/2013	1/16/2013	1
1/15/2013	1/16/2013	1
1/18/2013	2/19/2013	22
2/19/2013	2/19/2013	0
1/15/2013	1/15/2013	0
1/15/2013	1/16/2013	1
1/16/2013	1/18/2013	1
1/15/2013	1/15/2013	0
1/15/2013	1/16/2013	1
1/16/2013	1/18/2013	1
1/9/2013	1/9/2013	0
1/9/2013	1/9/2013	0
1/9/2013	1/10/2013	1
1/10/2013	1/10/2013	0
1/10/2013	1/10/2013	0
1/10/2013	1/10/2013	0
1/10/2013	1/10/2013	0
1/10/2013	1/10/2013	0
1/10/2013	1/11/2013	0
1/10/2013	1/10/2013	0
1/16/2013	1/29/2013	9
1/16/2013	1/29/2013	9
1/29/2013	2/1/2013	2
1/11/2013	1/11/2013	-1
1/11/2013	1/11/2013	-1
1/11/2013	1/11/2013	-1
1/11/2013	1/14/2013	1

Re: Calculating duration between two dates from different years

Did you ever try the formula in my reply? It was supposed to exclude weekdays and it works for me if the columns are in date format (not strings).

Re: Calculating duration between two dates from different years

This is calcuating same as using Date Difference..but this is including weekends as well..is there a way to calculate ONLY weekdays?

Re: Calculating duration between two dates from different years

This is working , but I dont want to include weekends in my calcuation..Is there any way to calculate only weekdays?

Re: Calculating duration between two dates from different years

If your start and end date columns are Continuous, Numeric, Date format; then the formula for the duration between the two columns in days could be something like: Date Difference(:Start Date, :End Date, "day")

If your date columns are character, then you can parse the text like PMroz did above with:

Date Difference(

informat(:Start Date, "m/d/y"),

informat(:End Date, "m/d/y"),

"day")

Re: Calculating duration between two dates from different years

This will give you time elapsed in days.

First, add a new numeric variable/column.

In the Formula Editor window, select first date, click subtract, select second date, then divided by, select Date Time function, in days, put a 1 in the parenthesis, click apply.

(:diagnosis_date - :dob_date) / In Days( 1 )

Re: Calculating duration between two dates from different years

How about using the Column Info and specify Start Date and End Date columns with Data Type = Numeric, Modeling Type = Continuous, Format=Date=m/d/y, Input Format=Date=m/d/y. Then add an additional column and using the Column Formula specify End Date-Start Date and also choose Format Duration :day:hr:min

Re: Calculating duration between two dates from different years

can you make it more general? I will explain my data clearly.. I have a column "Start Date" with format as Date (mm/dd/yyyy) and another column "End Date" with format as mm/dd/yyyy.I want to subtract start date from End date, my date are

Start Date End Date

10/31/2012 03/31/2013

09/15/2012 02/13/2013

08/15/2012 01/29/2013

Now I want to subtract End Date - Start Date to get the value in days

since start date is in 2012 and end dates are in 2013, iam not getting the correct value if I simply say :End Date - :Start Date

Re: Calculating duration between two dates from different years

1. This column formula should give the number of working days between the two days:

Try( Sum( Day Of Week( Index( :A, :E, 86400 ) ) < 6 ) - 1 )

Paste this into the Formula editor. The Try() is only needed if you have empty cells in the date column. The -1 is there to exclude the start (or end) date from the sum. 86400 is the number of seconds in 24 hours.

2. The column formula equivalent to PMroz suggestion would be:

(:E - :A) / 86400

Re: Calculating duration between two dates from different years

Can you provide more information? What is the data type and format of the A and E columns? Also, when you subtract dates you get the number of seconds between them. Here's a simple example that calculates the date difference in days:

adate = informat("10/31/2012", "m/d/y");

edate = informat("02/20/2013", "m/d/y");

cdate = (edate - adate) / 3600 / 24;

This results in

112

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