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Use IF statement with Graph Builder (Dispatch)

I have been trying for a while to write a code in JSL to manage the legend position as follows according to the value of uni_bat.

 

 

Graph builder( ...,<BR /><BR />//If statement...
//if(
//N items(uni_bat) == 1, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ),
//N items(uni_bat) == 2, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 3, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 4, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 5, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 6, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 7, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 8, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,7,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 9, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,7,8,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 10, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,7,8,9,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 11, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,7,8,9,10,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ), 
//N items(uni_bat) == 12, Dispatch( {}, "400", LegendBox, {Legend Position( {9, [0,1,2,3,4,5,6,7,8,9,10,11,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} )
//);\
// case for uni_bat == 1 
Dispatch( {}, "400", LegendBox, {Legend Position( {9,[0,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]} )} ),

Q1.

If only one line is executed like "case for uni_bat==1", the graph is created without any problem.

However, the IF statement is not well recognized in the graph builder.

How to properly run the sequence of numbers following the Legend Position with IF statement???

(ex. {9,[0,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1], 10, [-1, -1, -1, -1]})

 

 

Q2.

If Q1 is solved, is there a way to further simplify the code written with IF statement using For Loop ?

How to write Legend Position( ) code regularly until uni_bat==50 using for statement.

 

 

I would be very thankful for any suggestions.

 

AnalyticsData TableDOEGraphicsOtherScriptingWindowsRe: Use IF statement with Graph Builder (Dispatch)

The JSL code you are attempting to modify, can be more easily handled using messages sent to the Legend Box() messages.  Below is the entry from the Scripting Index that gives an example of modifying the Legend Position.  Using this method, your IF() statement structure will work as you assumed it would in your example.

Go to

     Help=>Scripting Index

to access the above display

 

Re: Use IF statement with Graph Builder (Dispatch)

Thanks Jim , I solved the issue for legend position.

Can you also answer Q2 below?

Q2.

is there a way to further simplify the code written with IF statement using For Loop ? How to write Legend Position( ) code regularly until uni_bat==50 using for statement.

Re: Use IF statement with Graph Builder (Dispatch)

You can generate the dynamic part of the Legend Position and build the required list

Names Default To Here( 1 );
uni_bat = {a, b, c, d};

theList = {9, 10, [-1, -1, -1, -1]};

mat = Shape( Matrix( Index( 1, N Items( uni_bat ) - 1 ) ), N Items( uni_bat ) - 1 ) |/ 
 [-1, -1, -1, -1, -1, -1, -1, -1, -1,-1, -1];

insert into(theList, mat, 2);

show(theList);

and then plug it into the Legend Position message as demonstrated in the below simplified example

Names Default To Here( 1 );
Open( "$SAMPLE_DATA/Big Class.jmp" );
gb = Graph Builder(
 Show Control Panel( 0 ),
 Variables(
  X( :height ),
  Y( :weight ),
  Overlay( :sex )
 ),
 Elements(
  Points( X, Y, Legend( 3 ) ),
  Smoother( X, Y, Legend( 4 ) )
 )
);
theList = {3, 4, [2, 1]};
mat = [4,3];
insert into(theList,mat,2);
eval(parse("Report( gb )[LegendBox( 1 )] << Legend Position( "||char(theList)||" );"));

Re: Use IF statement with Graph Builder (Dispatch)

 

Thanks to the example you provided in detail, ALL ISSUES (Q1, Q2) have been resolved.

 

theList = {9, 10, [-1, -1, -1, -1]}; <BR />mat = Shape( Matrix( Index(<FONT color="#FF0000"> 0,</FONT> N Items( uni_bat ) - 1 ) ), <BR />N Items( uni_bat ) ) |/ [-1, -1, -1, -1, -1, -1, -1, -1]; 

As above, in the script you gave me, I was able to make the result completely what I wanted by adding 0 in front of N items.

 

Thank you again Jim for always kind answers!!!

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