從迴圈追加矩陣我正在嘗試使用以下腳本生成矩陣並有幾個問題:
1.為了正確獲得“行”,我需要先對水果列進行排序嗎?是否有一個隨機公式可以從「r」中選出一個數字?
2.我需要最終的「運行」矩陣與furitName資訊(i變數)並且只是一個矩陣。我目前的腳本將產生 3 個運行矩陣(取決於 N 個專案(fruitName))
3. 一旦所有運行矩陣連接成一個,有沒有辦法將矩陣輸出到資料表?
愛!
Names Default To Here( 1 );
dt = Current Data Table();
Summarize( dt, fruitName = by( :fruit ) );
For( i = 1, i <= N Items( fruitName ), i++,
r = dt << get rows where( :fruit == fruitName[i] );
row = Random Integer( Max( r ) - Min( r ) );
/*show(r);
show(row);*/
runTime = 5;
run = [](0, 2);
For( j = 1, j <= runTime, j++,
row = Random Integer( Max( r ) - Min( r ) );
run |/= Matrix( {{j, dt:name( "price hi" )[row] - dt:price lo[row]}} );
);
Show( run );
);
自動化和腳本編寫回复:從循環中追加矩陣這是我認為您正在尋找的幾種方法
Names Default To Here( 1 );
dt = Current Data Table();
Summarize( dt, fruitName = by( :fruit ) );
runTime = 5;
run = [](0, 2);
fruitList ={};
For( i = 1, i <= N Items( fruitName ), i++,
r = dt << get rows where( :fruit == fruitName[i] );
For( j = 1, j <= runTime, j++,
insert into(fruitList, fruitName[i]);
row = r[Random Integer( nrows(r))];
run |/= Matrix( {{j, dt:name( "price hi" )[row] - dt:price lo[row]}} );
);
);
dtNew = New Table("Random",
add rows(n rows(run)),
new column("Fruit", character,set each value(fruitList[Row()])),
new column("Delta", set each value(run[row(),2]))
);
// or
dtNew2 = dt << Subset(
Sample Size( runTime ),
Selected columns only( 0 ),
Stratify( :fruit )
);
dtNew2 << New Column( "Delta", set each value( :price hi - :price lo ) );
dtNew2 << delete columns( {"price hi", "price lo"} );