你好!
按索引引用列的正確方法是什麼? 理想情況下,我正在尋找這樣的東西:

先感謝您!
您應該只能使用 Column(index)。
向數據列對象發送消息
col = Column( 2 ); // assign a reference to the second column
腳本可能是這樣,但在公式中我收到此錯誤:

有趣的是,彈出窗口提示可以提供號碼,但似乎並非如此

嘗試使用 << get name 而不是 Column Name()
Choose(:Block,
Column(1) << get name,
Column(2) << get name,
Column(3) << get name
)

完整示例:
Names Default To Here(1);
dt = New Table("Untitled",
Add Rows(3),
Compress File When Saved(1),
New Column("Block", Numeric, "Continuous", Format("Best", 12), Set Values([1, 2, 3])),
New Column("Column 2", Numeric, "Continuous", Format("Best", 12), Set Values([1, ., .])),
New Column("Column 3", Numeric, "Continuous", Format("Best", 12), Set Values([2, ., .])),
New Column("Column 4", Numeric, "Continuous", Format("Best", 12), Set Values([3, ., .])),
New Column("Formula",
Character,
"Nominal",
Formula(Choose(:Block, Column(1) << get name, Column(2) << get name, Column(3) << get name))
)
);