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動態數據匯總分析

我需要總結一個複雜的數據集。數據集包含一堆在過去 2 週內處理過的項目及其執行情況。為了衡量性能，我們對不同類別進行了評級。類別從 XZ001 到 XZ100。我也有子每個主要類別的類別。例如 - XZ008 有 YZ801 到 YZ809 子類別。

數據集是動態的。意味著 1 週的數據集可能有 YZ 899，但其他周可能沒有。

 

我將某些類別和子類別分為bucket1 和bucket2。所有其他類別將成為bucket3 的一部分。

下面是我嘗試編寫但似乎不起作用的腳本。

 

 

任何幫助表示讚賞。

cdt = open("C:\Documents\Data\out.csv");

cdt=current data table();
sum_lst2 = {};
sum_lst3 = {};
sum_lst4 = {};
col_lst2 = cdt << get column names( Numeric );
For( i = 1, i <= N Items( col_lst2 ), i++,
colname = Column( col_lst2[i] ) << get name;
If( Contains( {"XZ008","XZ010","XZ015","XZ053","YZ1374","YZ1375","YZ9429","YZ9792","YZ9908", "YZ1930","YZ1933","YZ2744","YZ4621","YZ4625","YZ4630","YZ4640","YZ4681","YZ4830"}, colname ) |(colname >= "YZ901" & colname <= "YZ916") |(colname >= "YZ954" & colname <= "YZ965") |(colname >= "YZ1360" & colname <= "YZ1371") |(colname >= "YZ2581" & colname <= "YZ2586") | (colname >= "YZ2900" & colname <= "YZ2950") | (colname >= "YZ3400" & colname <= "YZ3450"),
Insert Into( sum_lst2, col_lst2[i] )
); //Bucket1

If( Contains( {"XZ098","XZ090"}, colname ) | (colname >= "YZ9700" & colname <= "YZ9791") | (colname >= "YZ9793" & colname <= "YZ9799"),
Insert Into( sum_lst4, col_lst2[i] )
);
);//Bucket2


If(!Contains( {"XZ008","XZ010","XZ015","XZ053","XZ098","XZ090","YZ1374","YZ1375","YZ9429","YZ9792","YZ9908", "YZ1930","YZ1933","YZ2744","YZ4621","YZ4625","YZ4630","YZ4640","YZ4681","YZ4830"}, colname ) |(colname >= "YZ901" & colname <= "YZ916") |(colname >= "YZ954" & colname <= "YZ965") |(colname >= "YZ1360" & colname <= "YZ1371") |(colname >= "YZ2581" & colname <= "YZ2586") | (colname >= "YZ2900" & colname <= "YZ2950") | (colname >= "YZ3400" & colname <= "YZ3450")| (colname >= "YZ9700" & colname <= "YZ9791") | (colname >= "YZ9793" & colname <= "YZ9799"),
Insert Into( sum_lst3, col_lst2[i] )
); //Bucket3

 

Eval( Eval Expr( cdt << New Column( "Bucket1", formula( Sum( Expr( sum_lst2 ) ) ) ) ) );
Eval( Eval Expr( cdt << New Column( "Bucket3", formula( Sum( Expr( sum_lst3 ) ) ) ) ) );
Eval( Eval Expr( cdt << New Column( "Bucket2", formula( Sum( Expr( sum_lst4 ) ) ) ) ) );

 

樣本數據集：

 

物品	YZ0100	YZ0801	YZ0805	YZ0806	YZ0807	YZ0813	YZ0814	YZ0815	YZ0817	YZ0871	YZ0874	YZ0881	YZ1367	YZ1374	YZ1541	YZ1571	YZ1573	YZ1575	YZ1577	YZ1583	YZ1585	YZ1590	YZ1591	YZ1594	YZ1933	YZ2701	YZ2708	YZ2737	YZ2740	YZ2744	YZ2745	YZ2749	YZ2750	YZ3404	YZ3407	YZ3415	YZ3416	YZ3417	YZ3418	YZ3422	YZ3423	YZ3492	YZ3493	YZ3502	YZ3534	YZ4621	YZ4625	YZ4821	YZ9031	YZ9429	YZ9901	YZ9908	XZ001	XZ008	XZ013	XZ015	XZ019	XZ027	XZ034	XZ035	XZ046	XZ048	XZ090	XZ094	XZ099
AAA666	455						2																		1				1	5		1			1				1						5	3	1					22	455	2			1	7	2	5	4				22
AAA755	118																																																			6	118												6
AAA757	324	1					1																		7	1				33		3					1		3	1			1		3		1	1		1		8	324	2			7	37	6	3	1	1		1	8
BBA696	480									1		3													1							1			1										5		3	1				100	480	4			1	1	1	5	3	1			100
BBA786	155																										1												1							1						1	155					1	1		1				1
BBA787	197									1					1		1								1							2													7		1	1				59	197	1		2	1	2		7	1	1			59
CCA613	233											1																				1						1	1		1	1			2		1					12	233	1				1	4	2	1				12
CCA614	551				1																				1		2	1				7							2				1		4		4			1		69	551	1			1	10	3	4	4			1	69
CCA642	382					1					1	2												2								2					2		1		4			1	4	1	4					91	382	4		2		2	7	5	5				91
CCA642R	57																																										1									3	57						1						3
CCB613	165											1								1								1			1	2			2				1	1	1		1		1	1						52	165	1		1		4	6	1	1				52
DDA624	113	6		4				7	2																							1		1																		16	113	19				1	1						16
DDA631	561												1	1		5	6	3				3			2		1	1	1			3				1	1	1	1	1	1				1		3			1		30	561		2	17	2	6	6	1	3			1	30
DDA634	569															3	1		1		1	1	1		1							3				1	3		1	7	1	1	2		3		5		1		1	8	569			8	1	3	16	3	5		1		9
EEA624	228		1	1				1																								3							1	2	2	1								15	2	54	228	3				3	6					15	56
EEA627	495															12	15	7				3					1					1	2	2	1	1		1	3	5	2	1			7		3		1	2		28	495			37		4	16	7	3		1	2	28

數據表Re: 動態數據匯總分析

我在您的代碼中發現的唯一錯誤是您關閉了“)”

For( i = 1, i <= N Items( col_lst2 ), i++,

放在 Bucket 2 之後，而不是 Bucket 3 之後。

 

我做了一些額外的小修改，但據我所知，代碼有效

Names Default To Here( 1 );
cdt = Open( "C:\Documents\Data\out.csv" );

Current Data Table( cdt );

sum_lst2 = {};
sum_lst3 = {};
sum_lst4 = {};
col_lst2 = cdt << get column names( Numeric );
For( i = 1, i <= N Items( col_lst2 ), i++,
 colname = Column( col_lst2[i] ) << get name;
 If(
  Contains(
   {"XZ008", "XZ010", "XZ015", "XZ053", "YZ1374", "YZ1375", "YZ9429", "YZ9792", "YZ9908", "YZ1930", "YZ1933", "YZ2744",
   "YZ4621", "YZ4625", "YZ4630", "YZ4640", "YZ4681", "YZ4830"},
   colname
  ) | (colname >= "YZ901" & colname <= "YZ916") | (colname >= "YZ954" & colname <= "YZ965") | (colname >= "YZ1360" &
  colname <= "YZ1371") | (colname >= "YZ2581" & colname <= "YZ2586") | (colname >= "YZ2900" & colname <= "YZ2950") | (
  colname >= "YZ3400" & colname <= "YZ3450"),
  Insert Into( sum_lst2, col_lst2[i] )
 ); //Bucket1

 If(
  Contains( {"XZ098", "XZ090"}, colname ) | (colname >= "YZ9700" & colname <= "YZ9791") | (colname >= "YZ9793" & colname
   <= "YZ9799"),
  Insert Into( sum_lst4, col_lst2[i] )
 );//Bucket2

 If(
  !Contains(
   {"XZ008", "XZ010", "XZ015", "XZ053", "XZ098", "XZ090", "YZ1374", "YZ1375", "YZ9429", "YZ9792", "YZ9908", "YZ1930",
   "YZ1933", "YZ2744", "YZ4621", "YZ4625", "YZ4630", "YZ4640", "YZ4681", "YZ4830"},
   colname
  ) | (colname >= "YZ901" & colname <= "YZ916") | (colname >= "YZ954" & colname <= "YZ965") | (colname >= "YZ1360" &
  colname <= "YZ1371") | (colname >= "YZ2581" & colname <= "YZ2586") | (colname >= "YZ2900" & colname <= "YZ2950") | (
  colname >= "YZ3400" & colname <= "YZ3450") | (colname >= "YZ9700" & colname <= "YZ9791") | (colname >= "YZ9793" &
  colname <= "YZ9799"),
  Insert Into( sum_lst3, col_lst2[i] )
 ); //Bucket3
);
 

Eval( Eval Expr( cdt << New Column( "Bucket1", formula( Sum( Expr( sum_lst2 ) ) ) ) ) );
Eval( Eval Expr( cdt << New Column( "Bucket3", formula( Sum( Expr( sum_lst3 ) ) ) ) ) );
Eval( Eval Expr( cdt << New Column( "Bucket2", formula( Sum( Expr( sum_lst4 ) ) ) ) ) );

Re: 動態數據匯總分析更改 barcket 位置後，我的代碼正在工作，謝謝。但是 bucket3 中的數字是錯誤的。那是因為項目列中的 bucket3 值也被添加了。如何只包含列名稱以 XZ 和 YZ 開頭的列在第 3 桶？Re: 動態數據匯總分析

我不明白這個問題。以下列是為 Bucket 3 添加的列。

{YZ0100, YZ0801, YZ0805, YZ0806, YZ0807, YZ0813, YZ0814, YZ0815, YZ0817, YZ0871,
YZ0874、YZ0881、YZ1367、YZ1541、YZ1571、YZ1573、YZ1575、YZ1577、YZ1583、YZ1585、
YZ1590、YZ1591、YZ1594、YZ2701、YZ2708、YZ2737、YZ2740、YZ2745、YZ2749、YZ2750、
YZ3404、YZ3407、YZ3415、YZ3416、YZ3417、YZ3418、YZ3422、YZ3423、YZ3492、YZ3493、
YZ3502、YZ3534、YZ4821、YZ9031、YZ9901、XZ001、XZ013、XZ019、XZ027、XZ034、XZ035、
XZ046、XZ048、XZ094、XZ099}

哪些列不應該在那裡？

Re: 動態數據匯總分析我有一個 !contains 語句用於 bucket3。這些列都不需要添加。所有從“XZ”和“YZ”開始的列，除了在 bucket1 和 2 中添加的那些需要添加到 bucket3。Re: 動態數據匯總分析

啊，鑑於我錯過的邏輯，我認為需要如何陳述它是：

If(
  Contains(
   {"XZ008", "XZ010", "XZ015", "XZ053", "XZ098", "XZ090", "YZ1374", "YZ1375", "YZ9429", "YZ9792", "YZ9908", "YZ1930", "YZ1933", "YZ2744",
   "YZ4621", "YZ4625", "YZ4630", "YZ4640", "YZ4681", "YZ4830"},
   colname
  ) == 0,
  If(
   (colname >= "YZ901" & colname <= "YZ916") | (colname >= "YZ954" & colname <= "YZ965") | (colname >= "YZ1360" & colname <= "YZ1371") | (colname
    >= "YZ2581" & colname <= "YZ2586") | (colname >= "YZ2900" & colname <= "YZ2950") | (colname >= "YZ3400" & colname <= "YZ3450") | (colname
    >= "YZ9700" & colname <= "YZ9791") | (colname >= "YZ9793" & colname <= "YZ9799"),
   Insert Into( sum_lst3, col_lst2[i] )
  )
 ); //Bucket3