你好
请求有关编写“输出”(Output)列的脚本的帮助。
我有分配给不同事件的Sr ID列表,并且需要将LAB T0事件与特定事件匹配的结果输出列

将不得不提供帮助。 我已经为上面的屏幕快照附加了excel文件。
谢谢
小号
给定一个看起来像这样的数据表

在完成创建所需输出的步骤时,JMP以交互方式提供了以下脚本
// Clear row selection
Data Table( "Example File" ) << Clear Select;
// Data table summary
// → Data Table( "Subset of Untitled 9 By (Sr ID, Event)" )
Data Table( "Example File" ) << Summary(
Group( :Sr ID, :Event ),
Freq( "None" ),
Weight( "None" ),
Link to original data table( 0 )
);
// Select matching cells
Data Table( "Example File By (Sr ID, Event)" ) <<
Select Where( :Event == "LAB_T0" );
// Delete selected rows
Data Table( "Example File By (Sr ID, Event)" ) <<
Select Where( :Event == "LAB_T0" ) << Delete Rows;
// Delete column: N Rows
Data Table( "Example File By (Sr ID, Event)" ) << Delete Columns( :N Rows );
// Change column name: Event → Output
Data Table( "Example File By (Sr ID, Event)" ):Event << Set Name( "Output" );
// Update data tables
Data Table( "Example File" ) << Update(
With( Data Table( "Example File By (Sr ID, Event)" ) ),
Match Columns( :Sr ID = :Sr ID )
);
