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String to number conversion not working

ALopez

Hi, I have a regular expression that extracts the Year from a month_year i.e. "August_2020". However, I haven't been able to find the correct syntax to convert the character Year "cYear" to number so I can do math with it. I will appreciate any pointers. Thanks!!

Names Default To Here( 1 );

SelMonth = {"October_2020"};

cYear = (Regex Match (char(SelMonth), "\d{4}") );

//convert character year to number year

nYear = Num ("cYear");  //Scripting Guide p137

//Subtract 1 and get previous year

pYear = (nYear - 1);

//convert previous year to character

cpYear = Char ( pYear);

Accepted answers

txnelson

The variable "SelMonth" is a JMP List( i.e. {} ), therefore the value of variable "cYear" is a list

{"2020"}

Assuming there is a reason that "SelMonth" needs to be a List, the simple solution is to reference "cYear" with a subscript to get the value

nYear = Num (cYear[1]);

All comments

txnelson

The variable "SelMonth" is a JMP List( i.e. {} ), therefore the value of variable "cYear" is a list

{"2020"}

Assuming there is a reason that "SelMonth" needs to be a List, the simple solution is to reference "cYear" with a subscript to get the value

nYear = Num (cYear[1]);

ALopez

Ah! Yes, the first value of the list! Thanks TX,

Jeff_Perkinson

You've got a number of small, but understandable errors.

SelMonth = {"October_2020"};

The curly braces {} around your character string have created a one element list. I don't know if that was on purpose or not. If your actual problem (as opposed to this example that you've provided) involves a multi-element list (e.g. {"October_2020", "November_2020"}) then some of what is to follow would need to be adjusted. Let us know.

Remove the curly braces to get a character string value.

SelMonth = "October_2020";

The next issue is with your next line:

cYear = (Regex Match (char(SelMonth), "\d{4}") );

Regex Match() returns a list which is going to cause you problems in your next step. It's also overly complicated. Instead, the Word() function is your friend: If you learn only one Formula Editor function, Word() is the one.

cYear=Word(2, SelMonth, "_");

show(cYear);

/*:

cYear = "2020";

On to your next line:

nYear = Num ("cYear");

Here you've put your variable name in quotes which makes it a character literal instead of a variable name. Instead, you should have:

nYear = Num (cYear);

However, getting back to the Regex Match() function returning a list, that will cause a problem here. The Num() function won't take a list as an argument.

If you insist on using Regex Match(), you'll need to specify the element of the list you want to work on using square braces [] as an index.

nYear = Num (cYear[1]);

Note: If you take my suggestion to use the Word() function this is unnecessary.

Putting it all together here's what you need:

Names Default To Here( 1 );

SelMonth = "October_2020";

cYear = (Regex Match (char(SelMonth), "\d{4}") );

cYear=Word(2, SelMonth, "_");

//convert character year to number year

nYear = Num (cYear);  //Scripting Guide p137

//Subtract 1 and get previous year

pYear = (nYear - 1);

//convert previous year to character

cpYear = Char ( pYear);

ALopez

Thanks Jeff, I would definitely read more about the Word function. Thank you very much for taking the time to help me.
Best regards

ThuongLe

Or you can get last 4 letters of your variable and convert it to number which is easier than Regex function

a = "October_2020";
nYear = Num(Right(a, 4));