Here is the screenshot of jmp sample data , Wondering which is the correct GRR% .I think 49.75 is from Average- range method calculation and 24.76 is from anova method calculation. can anyone help me to understand
As already stated, your screen shot is incomplete. I will comment on the differences between the R-bar/d2 and typical estimation of standard deviation (s)...the R-bar method first tests the integrity of the data with respect to outliers (special cause) using a range chart (or MR chart). The typical estimation performs no such test and can, therefore, be biased due to the outlier data point.
I don't see any of the numbers you refer to in your first post (49.75 or 24.76)? It also looks like you don't actually have multiple parts in the study as the part variation is using the column you labeled Operator? Perhaps you could share your JMP data table?
