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幫助代碼

para = {"Age","Orientation","Preference","Salary","Number","SN","Years","Service"} //some of the column names needed 

main_table_col_remain = main_tab << get column names(string);

For( i = N Items( main_table_col_remain ), i > 0, i--,
 If(!Contains( main_table_col_remain[i],<FONT color="#FF0000"> ??</FONT> ) ,
  Remove From( main_table_col_remain, i )
 ));
 

我在“ ??”中放什麼部分？我已經在這段代碼周圍盤旋了一段時間。我想刪除未存儲在para中的列名。

Re: help with code

You had the comparison backwards.  You want to take the main_table_col_remain[1] and look into the para list to see if it is there then remove it from the main_table_co_remaining list

para = {"Age", "Orientation", "Preference", "Salary", "Number", "SN", "Years", "Service"}; //some of the column names needed 

main_table_col_remain = main_tab << get column names( string );

For( i = N Items( main_table_col_remain ), i > 0, i--,
 If( Contains( Para, main_table_col_remain[i] ),
  Remove From( main_table_col_remain, i, 1 )
 )
);

回复：幫助代碼

跟進問題，我如何調整此代碼，以便它不會單獨拆分？ 

for(i=1, i<=n, i++,
 if((contains item(Para[i], main_table_col_remain) == 1),
  param = main_table_col_remain[i];
  tempdt =eval(parse( " combined_tab << Split(
  Split By(:Source_Table),
  Split(:Name(\!"" ||param|| "\!")),
  Remaining Columns(Drop All),
  Sort by Column Property 
  )"
  ))));
  

回复：幫助代碼

如果我正確地閱讀了您想做的事，那麼您要做的就是將所有 main_table_col_remain 列同時進入拆分定義。  這是一個通過Big Class示例數據表中的Sex列對Height和Weight進行拆分的簡單示例

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/big class.jmp" );<BR />dt << Split(
 Split By( :sex ),
 Split( :height, :weight ),
 Remaining Columns( Drop All ),
 Sort by Column Property
);

對於數據表中的複雜名稱，我傾向於將：Name（）添加到數據表中的每個元素 main_table_col_remain，在您的情況下，將列表轉換為字符串

myString = ":Name( \!"" || char(main_table_col_remain[1]) || "\!" )";
For( I = 2, I<= N Items( main_table_col_remain ), i++,
     myString = myString || ", :Name( \!"" || char(main_table_col_remain[i]) || "\!" )" ;
);

然後您可以將整個列表添加到拆分中

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/big class.jmp" );

main_table_col_remain = dt << get column names( string, continuous );

myString = ":Name( \!"" || Char( main_table_col_remain[1] ) || "\!" )";
For( I = 2, I <= N Items( main_table_col_remain ), i++,
 myString = myString || ", :Name( \!"" || Char( main_table_col_remain[i] ) || "\!" )"
);

Eval(
 Parse(
  "
dtSplit = dt << Split(
 Split By( :sex ),
 Split( " || myString ||
  " ),
 Remaining Columns( Drop All ),
 Sort by Column Property
);"
 )
);