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帮助代码

para = {"Age","Orientation","Preference","Salary","Number","SN","Years","Service"} //some of the column names needed 

main_table_col_remain = main_tab << get column names(string);

For( i = N Items( main_table_col_remain ), i > 0, i--,
 If(!Contains( main_table_col_remain[i],<FONT color="#FF0000"> ??</FONT> ) ,
  Remove From( main_table_col_remain, i )
 ));
 

我在“ ??”中放什么部分？我已经在这段代码周围盘旋了一段时间。我想删除未存储在para中的列名。

回复：帮助代码

您进行了向后比较。  您要使用main_table_col_remain [1]并查看参数列表以查看其是否存在，然后将其从main_table_co_remaining列表中删除

para = {"Age", "Orientation", "Preference", "Salary", "Number", "SN", "Years", "Service"}; //some of the column names needed 

main_table_col_remain = main_tab << get column names( string );

For( i = N Items( main_table_col_remain ), i > 0, i--,
 If( Contains( Para, main_table_col_remain[i] ),
  Remove From( main_table_col_remain, i, 1 )
 )
);

回复：帮助代码

跟进问题，我如何调整此代码，以便它不会单独拆分？ 

for(i=1, i<=n, i++,
 if((contains item(Para[i], main_table_col_remain) == 1),
  param = main_table_col_remain[i];
  tempdt =eval(parse( " combined_tab << Split(
  Split By(:Source_Table),
  Split(:Name(\!"" ||param|| "\!")),
  Remaining Columns(Drop All),
  Sort by Column Property 
  )"
  ))));
  

回复：帮助代码

如果我正确地阅读了您想做的事，那么您要做的就是将所有 main_table_col_remain 列同时进入拆分定义。  这是一个通过Big Class示例数据表中的Sex列对Height和Weight进行拆分的简单示例

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/big class.jmp" );<BR />dt << Split(
 Split By( :sex ),
 Split( :height, :weight ),
 Remaining Columns( Drop All ),
 Sort by Column Property
);

对于数据表中的复杂名称，我倾向于将：Name（）添加到数据表中的每个元素 main_table_col_remain，在您的情况下，将列表转换为字符串

myString = ":Name( \!"" || char(main_table_col_remain[1]) || "\!" )";
For( I = 2, I<= N Items( main_table_col_remain ), i++,
     myString = myString || ", :Name( \!"" || char(main_table_col_remain[i]) || "\!" )" ;
);

然后您可以将整个列表添加到拆分中

Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/big class.jmp" );

main_table_col_remain = dt << get column names( string, continuous );

myString = ":Name( \!"" || Char( main_table_col_remain[1] ) || "\!" )";
For( I = 2, I <= N Items( main_table_col_remain ), i++,
 myString = myString || ", :Name( \!"" || Char( main_table_col_remain[i] ) || "\!" )"
);

Eval(
 Parse(
  "
dtSplit = dt << Split(
 Split By( :sex ),
 Split( " || myString ||
  " ),
 Remaining Columns( Drop All ),
 Sort by Column Property
);"
 )
);