你好
我有一個字段 START_TIME(日期時間格式),例如
15.06.2019 6:05
16.06.2019 8:12
17.06.2019 7:01 等
我想保留週六和周日的所有日子。
我想,通過提取我會收到一個像
START_TIME SAT_SUN
15.06.2019 6:05 7
16.06.2019 8:12 1
17.06.2019 7:01 2
那我就用keep 1s和7s吧。
我將如何使用 JSL 腳本來做到這一點?
我嘗試了類似的方法
dt << 新列 ("SAT_SUN",numeric,format(day of week(:START_TIME),"datetime")) ;
這似乎不起作用。
任何想法?
乾杯!
新手
如果需要,請使用“幫助 > 腳本索引”來查找有關命令如何工作的更多詳細信息;
NamesDefaultToHere(1);
// Make a table of random dates
n = 50;
startDate = Date DMY( 01, 1, 2016 );
endDate = Date DMY( 12, 10, 2016 );
dates = Sort Ascending( J( n, 1, Random Integer(startDate, endDate) ) );
dt = New Table( "Dates",
New Column( "Random dates", Numeric, "Continuous", Format( "ddMonyyyy h:m", 35 ), Set Values( dates )),
);
// Add a formula for the day of the week
nc = dt << New Column( "Day of the week",
Numeric,
"Continuous",
Format( "Best", 12 ),
Formula( Day Of Week( :Random dates ) ),
Value Labels(
{1 = "Sunday", 2 = "Monday", 3 = "Tuesday", 4 = "Wednesday", 5 = "Thursday",
6 = "Friday", 7 = "Saturday"}
),
Use Value Labels( 1 ),
);
// Make a subset table
r = dt << getRowsWhere(:Day of the week == 7 | :Day of the week == 1);
dt2 = dt << Subset(rows(r), LinkToOriginalDataTable(1));
dt2 << setName("Weekend Dates");
無需創建新列即可執行您想要的操作。這是一個簡單的腳本,可以滿足您的要求:
Names Default To Here( 1 );
dt = Open( "$SAMPLE_DATA/Aircraft Incidents.jmp" );
dt << select where( Day Of Week( :Event Date ) == 1 | Day Of Week( :Event Date ) == 7 );
dtsub = dt << subset( selected rows( 1 ), selected columns( 0 ) );