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是否可以在散点图中叠加点？（不改变点的形状）

您好JMP用户，我是新来的，所以请保持温和。
我正在编写一个脚本来制作两个变量（Var 1，Var 2）的双变量图，然后用第三个变量（Result）着色。这很简单，但我现在的问题是工程师想在图上找到第四个变量（描述）的标识符。所以我需要获取每个唯一的描述，将其映射到一个整数（可能有任意数量的描述），然后将该整数覆盖在相应的点上。如果他们想知道哪个整数对应于哪个描述，他们可以将鼠标悬停在该点上（我有描述“Labeled”）。
我附上了我想要的形象。出于某种原因，我无法将图片直接上传到帖子中。

New Table( "table",
 Add Rows( 40 ),
 New Column( "Var 1",
  Numeric,
  Ordinal,
  Format( "Best", 8 ),
  Set Values(
   [2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 6, 6, 6, 6,
   6, 6, 6, 6, 6, 6, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8]
  )
 ),
 New Column( "Var 2",
  Numeric,
  Ordinal,
  Format( "Best", 8 ),
  Set Selected,
  Set Values(
   [0.35, 0.375, 0.4, 0.425, 0.45, 0.475, 0.5, 0.525, 0.55, 0.575, 0.35,
   0.375, 0.4, 0.425, 0.45, 0.475, 0.5, 0.525, 0.55, 0.575, 0.35, 0.375,
   0.4, 0.425, 0.45, 0.475, 0.5, 0.525, 0.55, 0.575, 0.35, 0.375, 0.4,
   0.425, 0.45, 0.475, 0.5, 0.525, 0.55, 0.575]
  )
 ),
 New Column( "Result",
  Character,
  Nominal,
  Set Values(
   {"PASS", "PASS", "PASS", "FAIL", "FAIL", "FAIL", "FAIL", "FAIL", "FAIL",
   "FAIL", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS",
   "FAIL", "FAIL", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS",
   "PASS", "PASS", "FAIL", "PASS", "PASS", "PASS", "PASS", "PASS", "PASS",
   "PASS", "FAIL", "FAIL", "FAIL"}
  )
 ),
 New Column( "Description",
  Character,
  Nominal,
  Set Values(
   {"", "", "", "A", "A", "A", "A", "B", "B", "C", "", "", "", "", "", "",
   "", "", "B", "C", "", "", "", "", "", "", "", "", "", "C", "", "", "",
   "", "", "", "", "B", "B", "C"}
  )
 )
);

Graph Builder(
 Size( 499, 513 ),
 Show Control Panel( 0 ),
 Automatic Recalc( 0 ),
 Variables( X( :Var 1 ), Y( :Var 2 ), Color( :Result ) ),
 Elements( Points( X, Y, Legend( 4 ), Jitter( 1 ) ) ),
 SendToReport(
  Dispatch(
   {},
   "400",
   ScaleBox,
   {Legend Model( 4, Properties( 0, {Marker( "FilledSquare" )} ) )}
  ),
  Dispatch( {}, "Graph Builder", FrameBox, {Marker Size( 9 )} )
 )
);

Re：是否有可能在散点图上叠加点？（不改变点的形状）

一种方法是标记“描述”列，然后选择所有行，然后标记它们。

这个JSL做了同样的事情：

Data Table("table") << {
 Set Row States(
  [8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8,
  8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8]
 ),
 Set Label Columns( :Description )
};