我知道有辦法做到這一點,但也許有人可能在這裡的某個地方有答案。 有沒有辦法使用單個腳本按會計年度加入具有相似數字和分類數據的多個數據表?
示例是我嘗試使用的腳本。
Data Table( "confirmed_enrollment_FY2006" ) << Join(
With( Data Table( "confirmed_enrollment_FY2007", "confirmed_enrollment_FY2008", "confirmed_enrollment_FY2009" ) ),
Merge Same Name Columns,
Select(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
SelectWith(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
By Matching Columns(
:Mail Code = :Mail Code,
:ID = :ID,
:HH Key = :HH Key,
:Program # = :Program #,
:Order Number = :Order Number
),
Drop multiples( 0, 0 ),
Include Nonmatches( 1, 1 ),
Preserve main table order( 1 )
)
您可以嘗試加入前 2 個表並將結果用作與第 3 個表進行另一個聯接的參數,依此類推(請參見下面的腳本)。 我不確定您要做什麼,所以我可能會誤解您要實現的目標,但您也可以考慮將所有表放在一起,而不是加入,然後勾選“創建源表”以便跟踪哪個表每個人註冊的年份;不同表中具有相同名稱的列將自動排列。
((Data Table( "confirmed_enrollment_FY2006" ) << Join(
With( Data Table( "confirmed_enrollment_FY2007") ),
Merge Same Name Columns,
Select(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
SelectWith(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
By Matching Columns(
:Mail Code = :Mail Code,
:ID = :ID,
:HH Key = :HH Key,
:Program # = :Program #,
:Order Number = :Order Number
),
Drop multiples( 0, 0 ),
Include Nonmatches( 1, 1 ),
Preserve main table order( 1 )
)) << Join(
With( Data Table( "confirmed_enrollment_FY2008") ),
Merge Same Name Columns,
Select(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
SelectWith(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
By Matching Columns(
:Mail Code = :Mail Code,
:ID = :ID,
:HH Key = :HH Key,
:Program # = :Program #,
:Order Number = :Order Number
),
Drop multiples( 0, 0 ),
Include Nonmatches( 1, 1 ),
Preserve main table order( 1 )
)) << Join(
With( Data Table( "confirmed_enrollment_FY2009") ),
Merge Same Name Columns,
Select(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
SelectWith(
:Fiscal Year,
:Mail Code,
:ID,
:HH Key,
:Program #,
:Order Number,
:Order Date,
:Name( "# Confirmed Enrollments" )
),
By Matching Columns(
:Mail Code = :Mail Code,
:ID = :ID,
:HH Key = :HH Key,
:Program # = :Program #,
:Order Number = :Order Number
),
Drop multiples( 0, 0 ),
Include Nonmatches( 1, 1 ),
Preserve main table order( 1 )
));