<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />Hi JMP Gurus,
I'm currently using a Perl script to launch our JSL script. The Perl script looks for the default installation location of JMP in the program files folder. Since there are potentially 4 different versions of JMP running around our workplace, I ended up with the following implementation:
1. Attempt to launch the standard version executable of JMP 12 in: C:\Program Files\SAS\JMP\12\jmp.exe
2. If that file does't exists, then attempt to launch the pro version executable of JMP 12 in: C:\Program Files\SAS\JMPPRO\12\jmp.exe
3. If that file does't exists, then attempt to launch the standard version executable of JMP 11 in: C:\Program Files\SAS\JMP\11\jmp.exe
4. If that file does't exists, then attempt to launch the pro version executable of JMP 11 in: C:\Program Files\SAS\JMPPRO\11\jmp.exe
5. If that file does't exists, end in error.
My question is the following:
Is there an environment variable or something in windows that I can query to find out where JMP is installed in the user's machine? My fear is that there might be a user somewhere in our workplace that might have JMP installed in another disk partition. Thus, voiding my current implementation that looks for the jmp executable in the C:\ drive.
You can use OLE automation from Perl to run a JSL file:
use OLE;use Win32::OLE;my $jmp = Win32::OLE->new('JMP.Application');$jmp->{Visible} = 1;$jmp->RunJSLFile("C:\\jsl_file.jsl");For more information on JMP automation, check out the JMP Automation Reference
